A 16.6 kg dog is running northward at 2.98 m/s, while a 4.99 kg cat is running e
ID: 1683534 • Letter: A
Question
A 16.6 kg dog is running northward at 2.98 m/s, while a 4.99 kg cat is running eastward at 3.53 m/s. Their 79.9 kg owner has the same momentum as the two pets taken together. Find the direction and magnitude of the owner's velocity. theta= ? north of east v= ? m/s A 16.6 kg dog is running northward at 2.98 m/s, while a 4.99 kg cat is running eastward at 3.53 m/s. Their 79.9 kg owner has the same momentum as the two pets taken together. Find the direction and magnitude of the owner's velocity. theta= ? north of east v= ? m/sExplanation / Answer
m1 = 16.6 Kg v1 = 2.98 m/s p1 = m1v1 = 49.468 Kg m/s m2 = 4.99 Kg v2 = 3.53 m/s p2 = m2v2 = 17.6147 Kg m/s M = 79.9 Kg v = ? p = Mv = 79.9v Kg m/s ------------------------------------------------------------------ angle between p1 & p2 is 90 degrees so p = (p1^2 + p2^2) = (2447.083 + 310.277) = 52.510 kg m/s Hence v = 52.51/M = 52.51/79.9 = 0.657 m/s ------------------------------------------------------------ Direction = Tan-1[p2/p1] = Tan-1[17.6147/49.468] = 19.59 degrees ---------------------------------------------------------------Related Questions
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