One strategy in a snowball fight is to throw a snowball at a high angle over lev

Question

One strategy in a snowball fight is to throw a snowball at a high angle over level ground. While your opponent is watching that snowball, you throw a second one at a low angle timed to arrive before or at the same time as the first one. Assume that both snowballs are thrown with a speed of 35.0 m/s. The first one is thrown at an angle of 65.0° with respect to the horizontal.

(a) At what angle should the second snowball be thrown to arrive at the same point as the first?

(b) How many seconds later should the second snowball be thrown after the first in order for both to arrive at the same time?

Explanation / Answer

that is u*usin2/g where is the angle of projection for two angles the range can be the same when sin21=sin22 i.e1+2=90 degrees so the other one should be thrown at an angle of 90-65=25degrees (b) How many seconds later should the second snowball be thrown after the first in order for both to arrive at the same time? this 2u(sin2-sin1)/g=2*35(sin65-sin25)/19.6 solve

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