Two rods of equal length L = 1.60 m form a symmetric cross. The horizontal rod h

Question

Two rods of equal length L = 1.60 m form a symmetric cross. The horizontal rod has a charge of Q = 200.00 C, and the vertical rod a charge of -Q = -200.00 C. The charges on both rods are distributed uniformly along their length. Calculate the potential at the point P at a distance x = 3.40 m from one end of the horizontal rod.
[Answer: 7.84×109 V]
Two rods of equal length L = 1.60 m form a symmetric cross. The horizontal rod has a charge of Q = 200.00 C, and the vertical rod a charge of -Q = -200.00 C. The charges on both rods are distributed uniformly along their length. Calculate the potential at the point P at a distance x = 3.40 m from one end of the horizontal rod.

Explanation / Answer

please post a graph to show the configuration of 2 rods and the point P

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