A wagon is rolling forward on level ground. Friction is negligible. The person s

Question

A wagon is rolling forward on level ground. Friction is negligible. The person sitting in the wagon is holding a rock. The total mass of the wagon, rider, and rock is 96.0 kg. The mass of the rock is 0.330 kg. Initially the wagon is rolling forward at a speed of 0.510 m/s. Then the person throws the rock with a speed of 17.0 m/s. Both speeds are relative to the ground. Find the speed of the wagon after the rock is thrown directly forward.
m/s

Find the speed of the wagon after the rock is thrown directly backward.
m/s

Explanation / Answer

Given that The mass of wagon + rider+ rock = M = 92.5 kg The mass of rock = m = 0.330 kg Initial speed of wagon = u1 = 0.460 m/s speed of rock is v1 = 16.5 m/s Find the speed of the wagon after the rock is thrown directly forward. According to conservation of momentum we have Mu1= mv1 + (M-m)v2 v2 = (Mu1 - mv1 ) / ( M -m) = (92.5 * 0.460 - 0.330*16.5) / (92.5 - 0.330) = 0.4025 m/s Find the speed of the wagon after the rock is thrown directly backward. Mu1= - mv1 + (M-m)v2 v2 = (Mu1 + mv1 ) / ( M -m) = (92.5 * 0.460 + 0.330*16.5) / (92.5 - 0.330) = 0.5207 m/s

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.