Hooke\'s law describes a certain light spring of unstretched length32.0 cm. When

Question

Hooke's law describes a certain light spring of unstretched length32.0 cm. When one end is attached tothe top of a door frame, and a 7.20-kgobject is hung from the other end, the length of the spring is42.50 cm. (a) Find its spring constant.
1 kN/m

(b) The load and the spring are taken down. Two people pull inopposite directions on the ends of the spring, each with a force of170 N. Find the length of the springin this situation.
2 m
(a) Find its spring constant.
1 kN/m

(b) The load and the spring are taken down. Two people pull inopposite directions on the ends of the spring, each with a force of170 N. Find the length of the springin this situation.
2 m

Explanation / Answer

Unstretched length x= 32 cm
Stretched length x' = 42.5 cm
extension X = x ' - x = 10.5 cm =0.105 m
mass attached m = 7.2 kg
At equilibrium , kx = mg
from this spring constant k = mg / X
                            = 672 N / m                             = 0.762 kN / m (b). total force on spring F = 170 N + 170 N = 340N we know F = kX ' from this X ' = F / k                    = 0.5059 m                    = 50.59 cm length of the spring L = X ' + x                                 = 82.59 cm                                 = 0.8259 m                             = 0.762 kN / m (b). total force on spring F = 170 N + 170 N = 340N we know F = kX ' from this X ' = F / k                    = 0.5059 m                    = 50.59 cm length of the spring L = X ' + x                                 = 82.59 cm                                 = 0.8259 m

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