1. a) An air puck of mass 0.268 kg is tied to a string andallowed to revolve in
ID: 1682264 • Letter: 1
Question
1. a) An air puck of mass 0.268 kg is tied to a string andallowed to revolve in a circle of radus 1.06 m on a horizontal,frictionless table. The other end of the string passes through ahole in the center of the table and a mass of 1.44 kg is tied toit. The suspended mass remains in eqilibrium while the puckrevolves. The acceleration of gravity is 9.8 m/s^2. What is thetension in the string? Answer in units of N.b) What is the horizontal force acting on the puck? Answer inunits of N.
c) What is the speed of the puck? Answer in units ofm/s.
1. a) An air puck of mass 0.268 kg is tied to a string andallowed to revolve in a circle of radus 1.06 m on a horizontal,frictionless table. The other end of the string passes through ahole in the center of the table and a mass of 1.44 kg is tied toit. The suspended mass remains in eqilibrium while the puckrevolves. The acceleration of gravity is 9.8 m/s^2. What is thetension in the string? Answer in units of N. b) What is the horizontal force acting on the puck? Answer inunits of N. c) What is the speed of the puck? Answer in units ofm/s.
Explanation / Answer
Given thatmass of the air puck map =0.268 kg radius of the circle r = 1.06m suspended mas is ms = 1.44kg The tension in the stringis T =msg =1.44 kg *9.8m/s2 =14.112N =14.112N Therefore the horizontal forceacting on the puck is the tension itself so F = 14.112N The horizontal force that istension T provides the centripetal force as T =Fc = mapv2/r 14.11N = mapv2/r ==> v = 14.11 * 1.06 / 0.268
= 7.471 m/s
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