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How are you all doing this morning? Hoping great! Please I need someone to help

ID: 1681640 • Letter: H

Question

How are you all doing this morning? Hoping great! Please I need someone to help me solve theseproblems: 1) It goes thus, charge q1= 10nC is at the origin,charge q2= 16nC is on the x axix at x=4m, and chargeq3 =20 nC is at a point x = 4m and y = 4m. I wantto find the magnitude and direction of the resultant force onq2. Please help. Thanks How are you all doing this morning? Hoping great! Please I need someone to help me solve theseproblems: 1) It goes thus, charge q1= 10nC is at the origin,charge q2= 16nC is on the x axix at x=4m, and chargeq3 =20 nC is at a point x = 4m and y = 4m. I wantto find the magnitude and direction of the resultant force onq2. Please help. Thanks

Explanation / Answer

The force between the charges q1 and q2is F = k * (q1q2/r2) where k = (1/4o) = 9 * 109Nm2/C2,q1 = 10 nC = 10 *10-9 C,q2 = 16 nC = 16  *10-9 C and r = 4 m The force between the charges q3 and q2is F1 = k *(q3q2/r12) where q3 = 20 nC = 20 * 10-9 Cand r1 = [(4 - 4)2 + (4 -0)2]1/2 = 4 m The magnitude of the resultant force on q2 is Fr = F + F1 The direction of the resultant force on q2 is alongthe charge q1.This is because the magnitude of therepulsive force between q1 and q2 is largerthan the magnitude of the repulsive force between q3 andq2. The direction of the resultant force on q2 is alongthe charge q1.This is because the magnitude of therepulsive force between q1 and q2 is largerthan the magnitude of the repulsive force between q3 andq2.
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