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How far above the surface of the earth would you have to be beforeyour weight is

ID: 1681262 • Letter: H

Question

How far above the surface of the earth would you have to be beforeyour weight is reduced by 10.12%?

Explanation / Answer

Weight is calculated in Newtons --> mg=w Assuming your mass stays constant gravity would be the varyingfactor. g=GMm/(r^2) M is the mass of the earth m is your mass, but since weight is determined by mg themg=GMm/r^2 (the m's cancel out) radius of the earth is 6,378,100m G=6.67259 x 10-11 Nm2/kg2M=5.9742*10^24 kg g=9.8 however in this equation we want it to be 10.12%less. so g=9.8*0.8988=8.80824m/s/s 8.80824=GM/r^2 r=sqrt(GM/8.08824) r=sqrt(4.92856*10^13) r=7020371.333m r-r(earth)=7,020,371.333-6,378,100=   642,271.333 metersabove the earths surface.

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