there r 3 forces acting on a particle of mass m= 200g. oneforce is f1= 17 N. the

Question

there r 3 forces acting on a particle of mass m= 200g. oneforce is f1= 17 N. the other is f2= 23 N and it is actingperpendicular to the 1st one, and the 3rd is F3= 13 N and is actingin the opposite direction of the 2nd one (assume no other forcesare acting on the particle).
What is the acceleration of the particle? What is the displacement of the particle in 50 s if initiallyit was at rest? What is the velocity of the particle in t= 3 s
What is the acceleration of the particle? What is the displacement of the particle in 50 s if initiallyit was at rest? What is the velocity of the particle in t= 3 s

Explanation / Answer

F2 and F3 are opposite to each other.So. resultant F4 =F2-F3 = 23-13 = 10 N F4 and F1 are perpendicular to each other. So, net force F = [F1^ 2 + F4^ 2]                          =[17^2+10 ^ 2]                         = 19.72 N mass m = 200 g = 0.2 kg Accleration of the particle a = F / m = 98.61 m / s^2 (b). time t= 50 s initial velocity u = 0 from the relation S = ut + ( 1/ 2) at ^ 2                             = 0 + 123269.26 m = 123269.26 m (c). Velocity of the particle in t= 3 s is v = u + at'                                                              = 0 + (98.61*3)                                                               = 295.83 m / s

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