A flashlight on the bottom of a 4.28 m deep swimming pool sends a ray upward and

Question

A flashlight on the bottom of a 4.28 m deep swimming pool sends a ray upward and at an angle so that the ray strikes the surface of the water 2.78 m from the point directly above the flashlight. What angle (in air) does the emerging ray make with the water’s surface? Answer in units of ?. A flashlight on the bottom of a 4.28 m deep swimming pool sends a ray upward and at an angle so that the ray strikes the surface of the water 2.78 m from the point directly above the flashlight. What angle (in air) does the emerging ray make with the water’s surface? Answer in units of ?.

Explanation / Answer

tan (water) = 2.78/4.28=0.6495
water = 33.00 ,
so sin(water) = 0.54469 1.33 * sin(water) =1*sin(air) air. I come up with 46.42degrees.

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