M 1 has a massof 5.250 kg . It is on ahorizontal surface, connected by a massles
ID: 1680326 • Letter: M
Question
M1 has a massof 5.250 kg. It is on ahorizontal surface, connected by a massless string to a hook wheremass M2 canbe increased smoothly. The pulley has a negligible mass and nofriction. When M2 =2.473 kg it begins toaccelerate downwards at a rate of1.774 m/s2. Calculatesk between M1 and thesurface.Please include a free-body diagram along with yourdetailed calculation. Thank you!
Explanation / Answer
For mass m1 we have T - f = m1 a For mass m2, m2g - T = m2 a a) When mass m is just ready to move T = s m1g ==> m2g = s m1 g ==> s = m2 / m1 = 2.473 / 5.250 = 0.471 b) adding two equations we get m2 g - f = (m1 + m2)a ==> (m2 - m1 k) = (m1 + m2) (a/g) ==> 2.473 - 5.250 * k = 1.398 ==> k = 0.2047
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