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The problem says, \"A bicyclist in the Tour de France crests amountain pass as h

ID: 1680280 • Letter: T

Question

The problem says, "A bicyclist in the Tour de France crests amountain pass as he moves at 18 km/h. At the bottom, 4.0 kmfarther, his speed is 75 km/h. What was his average acceleration(in m/s) while riding down the mountain." I am able to get all the information, except for acceleration.I have that it is (v-v0)/t. They have  averageacceleration being (v^2-v0^2) / 2(x-x0). Where did they comeup with this equation?                                                                                                                                                                                                                                                                                  The problem says, "A bicyclist in the Tour de France crests amountain pass as he moves at 18 km/h. At the bottom, 4.0 kmfarther, his speed is 75 km/h. What was his average acceleration(in m/s) while riding down the mountain." I am able to get all the information, except for acceleration.I have that it is (v-v0)/t. They have  averageacceleration being (v^2-v0^2) / 2(x-x0). Where did they comeup with this equation?                                                                                                                                                                                                                                                                                 

Explanation / Answer

    from the problem to determine averageaccleration we use kinematic equation                        v2 - u2 = 2as             where initial velocity u = v0 = 5m/s                          s = the displacement = x - x0 = 4km = 4000m                          v2 - v02 = 2a (x-x0)                              a = v2 - v02/2(x-x0) plug in values a = -----m/s2