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The free-fall acceleration on Mars is 3.7 m/s 2 . (a) What length pendulum has a

ID: 1680149 • Letter: T

Question

The free-fall acceleration on Mars is 3.7 m/s2. (a) What length pendulum has a period of 4-s on the earth?
cm
What length pendulum would have a 4-s period on Mars?
cm

(b) An object is suspended from a spring with force constant 10N/m. Find the mass suspended from this spring that would result ina 4 s period on Earth and onMars. Earth kg Mars kg

(a) What length pendulum has a period of 4-s on the earth?
cm
What length pendulum would have a 4-s period on Mars?
cm

(b) An object is suspended from a spring with force constant 10N/m. Find the mass suspended from this spring that would result ina 4 s period on Earth and onMars. Earth kg Mars kg

Earth kg Mars kg

Explanation / Answer

Given that the acceleration due to gravity on Mars is g1 = 3.7m/s2            time period on the earth is T = 4.0s -------------------------------------------------------------------------------------------------   (a)        Time period is T = 2 L /g                                   L = T2g / 42                                       = (4.0s)2*9.8m/s2 /42                                           =------------ m           Thelength in the Mars is L = T2g1 /42                                                  = (4.0s)2*3.7m/s2 /42                                                       =------------ m   (b) If the force constant of the spring is K= 10 N/m         Time period is T =4.0s            Time period of verticle spring is T =  2m /K                                                              m= T2K / 42
                                                                                     = ------------- kg    it is same in earth and Mars since mass doesnot depends on the value of g                                                                      = (4.0s)2*9.8m/s2 /42                                           =------------ m           Thelength in the Mars is L = T2g1 /42                                                  = (4.0s)2*3.7m/s2 /42                                                       =------------ m   (b) If the force constant of the spring is K= 10 N/m         Time period is T =4.0s            Time period of verticle spring is T =  2m /K                                                              m= T2K / 42
                                                                                     = ------------- kg    it is same in earth and Mars since mass doesnot depends on the value of g                               
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