Show that using lambda = d sin( theta ) for a diffraction grating leads to lambd

Question

Show that using lambda = d sin( theta ) for a diffraction grating leads to lambda = d sin for this experimental arrangement. This was equation (12) from the Physical Optics lab manual. What does classical theory say about the planetary model of the atom? It doesn't work because planets are much more massive than electrons and the sun is hotter than the nucleus of an atom. It is a stable system with no radiation spectrum. It is an unstable system; the electrons spiral to the nucleus producing a continuous radiation spectrum. It is a stable system; when the electrons transition between energy levels, they emit a spectrum with discrete lines.

Explanation / Answer

1) = dsin() tan = x/L, so = arctan(x/L) = d sin[arctan(x/L)] 2) C

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