A 54.0 kg ice skater is moving at3.96 m/s when she grabs the loose endof a rope,

Question

A 54.0 kg ice skater is moving at3.96 m/s when she grabs the loose endof a rope, the opposite end of which is tied to a pole. She thenmoves in a circle of radius 0.803 maround the pole. (a) Determine the force exerted by thehorizontal rope on her arms.
1 N

(b) Compare this force with her weight by finding the ratio of theforce to her weight.
2 (a) Determine the force exerted by thehorizontal rope on her arms.
1 N

(b) Compare this force with her weight by finding the ratio of theforce to her weight.
2

Explanation / Answer

(a) The force exerted by the rope is the centripetal force: Fc = mv2/r = (54.0)(3.96)2/(0.803)= 1054 N (b) The ratio is: Fg = mg = (54.0)(9.8) = 529.2 N Fc/Fg = (1054 N)/(529.2 N) = 1.99

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