The work function for gold is 5.1 eV. (a) Convert the value of the work function
ID: 1679529 • Letter: T
Question
The work function for gold is 5.1 eV. (a) Convert the value of the work function fromelectron volts to joules.1 J
(b) Find the cutoff frequency for gold.
2 Hz
(c) What maximum wavelength of light incident on gold releases photoelectrons from the gold's surface?
3 m
(d) If light of energy 8.8 eV is incidenton gold, what is the maximum kineticenergy of the ejected photoelectrons? Give the answer in electronvolts.
4 eV
(e) For photons of energy 8.8 eV, whatstopping potential would be required to arrest the current ofphotoelectrons?
5 V (a) Convert the value of the work function fromelectron volts to joules.
1 J
(b) Find the cutoff frequency for gold.
2 Hz
(c) What maximum wavelength of light incident on gold releases photoelectrons from the gold's surface?
3 m
(d) If light of energy 8.8 eV is incidenton gold, what is the maximum kineticenergy of the ejected photoelectrons? Give the answer in electronvolts.
4 eV
(e) For photons of energy 8.8 eV, whatstopping potential would be required to arrest the current ofphotoelectrons?
5 V
Explanation / Answer
a) = 5.1eV = 5.1 *1.6*10-19J = 8.16x 10-19J b) fc = / h = 8.16 x10-19 / 6.63 x 10-34 = 1.23 x 1015Hz c) c = c / fc = 3 x108 / 1.23 x 1015 = 2.439 x10-7 m d) Max KE = 8.8eV - 5.1eV = 3.7eV e) V = KE / q = 3.7 x 1.602 x 10-19 / 1.6 x10-19 = 3.7 V
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