Thanks for looking at my question. On a rainy day, raindrops fall with a vertica

Question

Thanks for looking at my question.

On a rainy day, raindrops fall with a vertical velocity of 10.1m/s. If a car drives through the rain at 88.0 km/hr, what is themagnitude of the velocity of the raindrops relative to the car?=2.64×101 m/s

At what angle are the raindrops falling relative to the car? Assumethe direction the car is headed is 0° and down is90°.

How do you find the angle the raindrops are falling relative tocar? I am using tan theta= Ry/Rx. I get 67.5 degrees, but it ismarked wrong.
Cheers, and thank you again.

Explanation / Answer

Ans. The car moving in horizontal direction withvelocity=88.0 k.m/hr=88*5/18 m/s=24.44 m/s             velocity of rain drop relative tocar=(24.44^2+10.1^2)=26.4 m/s=2.64*10^1 m/s [Ans.]             the angles of rain drops falling relative tocar=tan-1(10.1/26.4)=20.9 degree. [Ans.]

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