1. A cheetah is walking at a speed of 1.15 m/s when it observes agazelle 43.0 m

Question

1. A cheetah is walking at a speed of 1.15 m/s when it observes agazelle 43.0 m directly ahead. If the cheetah accelerates at 9.25m/s2, how long does it take the cheetah to reach thegazelle if the gazelle doesn't move?
2.A hammer is accidentallydropped from rest down a vertical mine shaft. How long does it takefor the rock to reach a depth of 79 m? Neglect airresistance.
3.Neglecting air resistance,what maximum height will be reached by an arrow launched straightupward with an initial speed of 35 m/s?
2.A hammer is accidentallydropped from rest down a vertical mine shaft. How long does it takefor the rock to reach a depth of 79 m? Neglect airresistance.
3.Neglecting air resistance,what maximum height will be reached by an arrow launched straightupward with an initial speed of 35 m/s?

Explanation / Answer

Initial speed u = 1.15 m / s distance S= 43 m Accleration a= 9.25 m / s ^ 2 from the relation S = ut + ( 1/ 2) at ^ 2                    43 = 1.15 t + 4.625 t ^ 2 4.625 t ^ 2 + 1.15 t -43 = 0 t = { -1.15±[ 1.15^ 2 - 4(4.625)(-43) ] }/ 2( 4.625)    = { -1.15± 28.22 } / 2(4.625)    = 2.927 s (b). depth h = 79 m Initial velocity u = 0 required time t= [ 2h / g ]                       = 4.015 s (3) Initial speed v = 35 m / s Required height H = v ^ 2/ 2g                              = 62.5 m

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