A 312 eV electron is moving in the positive x direction. Itencounters a magnetic

Question

A 312 eV electron is moving in the positive x direction. Itencounters a magnetic field of 1.80 mT out of the paper.       e---> field B=1.80 mT out of paper a.) What is the velocity of the electron? b.) What is the radius of the circle or rotation? c.) What is the angular velocity? d.) Does the electron rotate clockwise orcounterclockwise?
Any help will be appreciated.
      e---> field B=1.80 mT out of paper a.) What is the velocity of the electron? b.) What is the radius of the circle or rotation? c.) What is the angular velocity? d.) Does the electron rotate clockwise orcounterclockwise?
Any help will be appreciated.

Explanation / Answer

Potential difference V = 312 V

Speed of electron v = [ 2Vq / m]

Where q = charge = 1.6 * 10 ^ -19 C

m = mass = 9.11* 10 ^ -31 kg

plug the values we get v = 10.46* 10 ^ 6 m / s

(b). In magnetic field Bvq = mv ^ 2/ r

From this radius r= mv / Bq

Where B = magnetic field = 1.8 * 10 ^ -3 T

Plug the values we get r = 0.03311 m

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