A cyclist is coasting @ a steady speed of 12m/s but enters amuddy stretch where

Question

A cyclist is coasting @ a steady speed of 12m/s but enters amuddy stretch where the effective coefficient of friction is 0.60.Will the cyclist emerge from the muddy stretch without having topedal if the mud lasts for 11m? If so what will be the speed uponemerging. When I get down to V^2-12^2=2x(-5.88)x11 id don't come up with3.53m/s could you explain to me what I'm doing wrong in detail andhow I would actually key it into the calculator? Thank you for allof your help. A cyclist is coasting @ a steady speed of 12m/s but enters amuddy stretch where the effective coefficient of friction is 0.60.Will the cyclist emerge from the muddy stretch without having topedal if the mud lasts for 11m? If so what will be the speed uponemerging. When I get down to V^2-12^2=2x(-5.88)x11 id don't come up with3.53m/s could you explain to me what I'm doing wrong in detail andhow I would actually key it into the calculator? Thank you for allof your help.

Explanation / Answer

V^2-12^2=2x(-5.88)x11    V2 - 12 * 12 = -129.36 V2 - 144 = -129.36 = V2 = -129.36 + 144 = 14.64 V= 14.64 = 3.82m/s answer is 3.82m/s not 3.53m/s

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