a. What is the equivalent resistance of the circuit? b. What is the current from

Question

a. What is the equivalent resistance of the circuit? b. What is the current from the battery? c. What is the voltage drop across the 4 ohm resistor?

Explanation / Answer

The 9 ohm and the 18 ohm resistors in parallel => (9*18 )/(18+9)=162/27=6..................................1 Then 5 ohm and the 20 ohm in parallel => (5*20)/(5+20)=100/25=4...........................2 Then the 4 ohm and 8 ohm in series =>8+4 =12.............................3 now the 6 ohm from equation 1 and the 4 ohm from equation 2 inparallel =>(4*6)/(4+6) =24/10=2.4............................4 Now the 2.4 ohm from equation 4 and the 12 ohm from equation 3 inparallel => (2.4*12)/(2.4+12) =28.8/14.4 =2 ohm a)so the equivalent resistance is 2 ohm The current I =V/R From figure V=6v and from calculatio R=2 ohm => b)I=6v/2ohm =3A =>

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