A tiger leaps horizontally from 6.5m high rock with a speed of3.5m/s. How far fr

Question

A tiger leaps horizontally from 6.5m high rock with a speed of3.5m/s. How far from the base of the rock will she land? S=Vot+1/2gt^2 6.5m = 0+1/2(9.80)t^2 6.5x2/9.80 I'm not coming up with 1.15. I get 1.326530612which I round to 1.33 can you tell me in detail what I'm missing? Iguess this is the reason I'm having a problem with the nex problemtoo. Thank you in advance for your help. A tiger leaps horizontally from 6.5m high rock with a speed of3.5m/s. How far from the base of the rock will she land? S=Vot+1/2gt^2 6.5m = 0+1/2(9.80)t^2 6.5x2/9.80 I'm not coming up with 1.15. I get 1.326530612which I round to 1.33 can you tell me in detail what I'm missing? Iguess this is the reason I'm having a problem with the nex problemtoo. Thank you in advance for your help.

Explanation / Answer

mulitply that by horizontal speed to get distancedtraveled!



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