Why do power companies use low currents in power lines whentransferring electric

Question

Why do power companies use low currents in power lines whentransferring electrical energy over large distances?

Because power lines have resistance andresistors transform electrical energy into heat. The lower thecurrent the lower the resistance of the power lines and hence theless electrical energy is lost to heat. Because power lines have resistance andresistors transform electrical energy into heat. The lower thecurrent, the less heat generated (and hence the less electricalenergy lost).    

Because power lines have resistance andresistors transform electrical energy into thermal energy.According to Ohm's Law, the lower the current the lower thevoltage. Thus both the voltage & current will be low and hencethe power loss will be small. Because power lines have resistance andresistors transform electrical energy into thermal energy. Highcurrents would require larger power lines to reduce the amount ofheat loss and hence be much more expensive than the small powerlines that low currents require. Because power lines have resistance andresistors transform electrical energy into heat. The lower thecurrent the lower the resistance of the power lines and hence theless electrical energy is lost to heat. Because power lines have resistance andresistors transform electrical energy into heat. The lower thecurrent, the less heat generated (and hence the less electricalenergy lost).    

Because power lines have resistance andresistors transform electrical energy into thermal energy.According to Ohm's Law, the lower the current the lower thevoltage. Thus both the voltage & current will be low and hencethe power loss will be small. Because power lines have resistance andresistors transform electrical energy into thermal energy. Highcurrents would require larger power lines to reduce the amount ofheat loss and hence be much more expensive than the small powerlines that low currents require.

Explanation / Answer

since the loss in power line is i^2 r where io is the current through the power line hence using low current implies low loss

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