A crate of fruit with a mass of 37.5 kg and a specific heatcapacity of 3700 J/(k

Question

A crate of fruit with a mass of 37.5 kg and a specific heatcapacity of 3700 J/(kg*K) slides 7.40 m down a ramp inclinedat an angle of 36.1 degrees below the horizontal.
If the crate was at rest at the top of theincline and has a speed of 2.75m/s at the bottom, how muchwork W1 on the crate by friction? Use 9.81 m/s^2 for the acceleration due togravity and express your answer in joules. Answer is 1530 Need Answer to Part B
If anamount of heat equal to the magnitude of the work done by frictionis absorbed by the crate of fruit and the fruit reaches a uniformfinal temperature, what is its temperature change T ? T= __________ C If the crate was at rest at the top of theincline and has a speed of 2.75m/s at the bottom, how muchwork W1 on the crate by friction? Use 9.81 m/s^2 for the acceleration due togravity and express your answer in joules. Answer is 1530 Need Answer to Part B
If anamount of heat equal to the magnitude of the work done by frictionis absorbed by the crate of fruit and the fruit reaches a uniformfinal temperature, what is its temperature change T ? T= __________ C

Explanation / Answer

Heat absorbed Q = 1530 J

Mass m = 37.5 kg

Specific heat capacity C = 3700 J / kg oC

We know Q = mC dt

From this temperature change dt = Q / mC

Plug the values we get dt = 0.011 oC

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