The primary coil of a transformer has 3,241 loops. The secondary coil has 993,65

Question

The primary coil of a transformer has 3,241 loops. The secondary coil has 993,650 loops. The primary coil has a 92 A current and 53 V.

a.) Is this a step-up or step-down transformer? How do you know?Choose one of the following. 1 It is a step-downtransformer because all transformers are step-downtransformers. It is a step-uptransformer because all transformers are step-uptransformers.     It is astep-down transformer because the primary currentis greater than the primary voltage. It is astep-down transformer because the secondary hasmore loops than the primary. It is astep-up transformer because the secondary has moreloops than the primary. It is astep-up transformer because the primary current isgreater than the primary voltage.

b.) Determine the power of the primary coil.
2 W
c.) Assuming no losses, determine the power of the secondarycoil.
3 W
d.) Calculate the voltage in the secondary coil.
4 V
e.) Calculate the current in the secondary coil.
5 A 1 It is a step-downtransformer because all transformers are step-downtransformers. It is a step-uptransformer because all transformers are step-uptransformers.     It is astep-down transformer because the primary currentis greater than the primary voltage. It is astep-down transformer because the secondary hasmore loops than the primary. It is astep-up transformer because the secondary has moreloops than the primary. It is astep-up transformer because the primary current isgreater than the primary voltage. 1 It is a step-downtransformer because all transformers are step-downtransformers. It is a step-uptransformer because all transformers are step-uptransformers.     It is astep-down transformer because the primary currentis greater than the primary voltage. It is astep-down transformer because the secondary hasmore loops than the primary. It is astep-up transformer because the secondary has moreloops than the primary. It is astep-up transformer because the primary current isgreater than the primary voltage. 1

Explanation / Answer

. Problem statement: The primary coil of a transformer has3,241 loops. The secondary coil has993,650 loops. The primary coil has a92 A current and 53 V.
(a) Is this a step-up or step-down transformer? How do you know?Choose one of the following.
___It is astep-down transformer because all transformers arestep-down transformers.
___It is astep-up transformer because all transformers arestep-up transformers. ___It is astep-down transformer because the primary currentis greater than the primary voltage. ___It is astep-down transformer because the secondary hasmore loops than the primary. _X_It is a step-uptransformer because the secondary has more loops than theprimary. ___It is astep-up transformer because the primary current isgreater than the primary voltage.
(b) Determine the power of the primary coil.
(c) Assuming no losses, determine the power of the secondarycoil.
(d) Calculate the voltage in the secondary coil.
(e) Calculate the current in the secondary coil. . 01.   Pprimary = power of the primarycoil = (V)*(I) = (53 volts)*(92 Ampere) = 4876 Watts 02.   Psecondary = power of the secondarycoil = (efficiency)*(Pprimary) = (1.0)*(4876 Watts) =4876 Watts 03.   Vsecondary = (turnsratio)*(Vprimary) = [(993650 loops)/(3241 loops)]*(53volts) = 16249.1volts 04.   Isecondary =(Psecondary)/(Vsecondary) = (4876Watts)/(16247.7 volts) = 0.300077 Ampere . ___It is astep-up transformer because the primary current isgreater than the primary voltage.
(b) Determine the power of the primary coil.
(c) Assuming no losses, determine the power of the secondarycoil.
(d) Calculate the voltage in the secondary coil.
(e) Calculate the current in the secondary coil. . 01.   Pprimary = power of the primarycoil = (V)*(I) = (53 volts)*(92 Ampere) = 4876 Watts 02.   Psecondary = power of the secondarycoil = (efficiency)*(Pprimary) = (1.0)*(4876 Watts) =4876 Watts 03.   Vsecondary = (turnsratio)*(Vprimary) = [(993650 loops)/(3241 loops)]*(53volts) = 16249.1volts 04.   Isecondary =(Psecondary)/(Vsecondary) = (4876Watts)/(16247.7 volts) = 0.300077 Ampere .

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