Twocapacitors, C 1 = 30µF and C 2 = 3.0µF, are connected in parallel and charged
ID: 1677441 • Letter: T
Question
Twocapacitors, C1 = 30µF and C2 = 3.0µF, are connected in parallel and charged with a 110 V power supply.(b) What potential difference would be required across the same twocapacitors connected in series in order that the combination storethe same energy as in (a)?
2 V Twocapacitors, C1 = 30µF and C2 = 3.0µF, are connected in parallel and charged with a 110 V power supply.
(b) What potential difference would be required across the same twocapacitors connected in series in order that the combination storethe same energy as in (a)?
2 V Twocapacitors, C1 = 30µF and C2 = 3.0µF, are connected in parallel and charged with a 110 V power supply.
(b) What potential difference would be required across the same twocapacitors connected in series in order that the combination storethe same energy as in (a)?
2 V
(b) What potential difference would be required across the same twocapacitors connected in series in order that the combination storethe same energy as in (a)?
2 V
Explanation / Answer
a ) Two Capacitors C1 = 30F C2 = 3.0 F are in parallel C equivalent is C ' =C1 + C2 = 30F + 3.0F = 33.0F Energy stored E = 1 /2 CV2 = 1 /2 ( 33.0 F ) ( 110V )2 = 0.199 J b ) Capacitors are connected in series Cs = C1 C2 /C1+C2 = 30F *3.0F / 30F +3.0F = 2.72F E = 1 /2CV2 0.199 J = 1 / 2 ( 2.72 F ) ( V2 ) Potential difference V = 382.5 V
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