A woman on a rocket traveling at 0.62c (withrespect to Earth) observes a meteor

Question

A woman on a rocket traveling at 0.62c (withrespect to Earth) observes a meteor come towards her and pass herat 0.91c. How fast is the meteor moving with respect to Earth?
c
0.91c = (u + 0.62c) / [ 1 + (u0.62c/c²) ]
0.91c = (u + 0.62c) / [ 1 + (u0.62/c) ]
0.91c[ 1 + (u0.62/c) ] = (u + 0.62c)
0.91c + 0.5642u = u + 0.62c
0.4358u = 0.91c – 0.62c
0.4358u = 0.29c
u = 0.665c
Should it be a negative since the meteor is coming towardher??? A woman on a rocket traveling at 0.62c (withrespect to Earth) observes a meteor come towards her and pass herat 0.91c. How fast is the meteor moving with respect to Earth?
c
0.91c = (u + 0.62c) / [ 1 + (u0.62c/c²) ]
0.91c = (u + 0.62c) / [ 1 + (u0.62/c) ]
0.91c[ 1 + (u0.62/c) ] = (u + 0.62c)
0.91c + 0.5642u = u + 0.62c
0.4358u = 0.91c – 0.62c
0.4358u = 0.29c
u = 0.665c
Should it be a negative since the meteor is coming towardher???

Explanation / Answer

Given u = 0.62 c

          V= 0.91c

          v=?

we know V = (u+v) / [ 1+(uv/c^ 2)]

           0.91c= (0.62 c + v ) / [ 1+0.62 cv / c ^ 2 ]

                    = (0.62 c + v) / [ 1+(0.62v / c ) ]

                    = (0.62c + v ) / [ ( c+0.62v ) / c ]

                    = c ( 0.62c+v) / ( 0.62v+c)

            0.91 = ( 0.62c+v) / ( 0.62v+c)

0.91(0.62v+c) = 0.62c + v

0.5642 v + 0.91c = 0.62c + v

      0.4358 v = 0.29 c

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