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A weight lifter raises a 905 N weighta vertical distance of 1.90 m in a timeinte

ID: 1676906 • Letter: A

Question

A weight lifter raises a 905 N weighta vertical distance of 1.90 m in a timeinterval of 1.95 s. Compute the powerprovided by the weight lifter's force.
W
How fast must a 102.2-kilogram personwalk or run to have the same kinetic energy as a 15.5-gram bulletthat has a speed of 226 m/s?
Person's speed: m/s

A weight lifter raises a 905 N weighta vertical distance of 1.90 m in a timeinterval of 1.95 s. Compute the powerprovided by the weight lifter's force.
W
How fast must a 102.2-kilogram personwalk or run to have the same kinetic energy as a 15.5-gram bulletthat has a speed of 226 m/s?
Person's speed: m/s

Person's speed: m/s

Explanation / Answer

power = work / time = 905 * 1.90 / 1.95   =    882 W . KE = (1/2) m v2 .     (1/2) m v2   ofperson   = (1/2) m v2 of bullet .           102.2 * v2   = 0.0155 * 2262 .    v =   2.783 m/s    is thepersons speed .    v =   2.783 m/s    is thepersons speed
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