A car initially traveling at 24.7 m/sundergoes a constant negative acceleration

Question

A car initially traveling at 24.7 m/sundergoes a constant negative acceleration of magnitude1.50 m/s2 after its brakesare applied. (a) How many revolutions does each tire makebefore the car comes to a stop, assuming the car does not skid andthe tires have radii of 0.330 m?
1 rev

(b) What is the angular speed of the wheels when the car hastraveled half the total distance?
2 rad/s
(a) How many revolutions does each tire makebefore the car comes to a stop, assuming the car does not skid andthe tires have radii of 0.330 m?
1 rev

(b) What is the angular speed of the wheels when the car hastraveled half the total distance?
2 rad/s

Explanation / Answer

equation of motion v(t)=24.7 -1.5*t time to stop v(t)=0 =>t=16.47 s revolutions: 24.7/0.33*t*1/2=196.2 rev (b) the angular speed of the wheels when the car hastraveled half the total distance s(t)=24.7*t-1/2*1.5*t2 s(t)=1/2*s(16.47)= 101.7 m =>t=4.82 s => angular speed =v(4.82)/0.33=52.9rad/s s(t)=1/2*s(16.47)= 101.7 m =>t=4.82 s => angular speed =v(4.82)/0.33=52.9rad/s

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