An aluminum rod 33.5 cm long at 22.2°C is heated to114°C. What is its new length

Question

An aluminum rod 33.5 cm long at 22.2°C is heated to114°C. What is its new length? Aluminum has a linear expansioncoefficient of 25 x 10-6 /C°.
Length of bar at final temperature in cm? An aluminum rod 33.5 cm long at 22.2°C is heated to114°C. What is its new length? Aluminum has a linear expansioncoefficient of 25 x 10-6 /C°.
Length of bar at final temperature in cm? An aluminum rod 33.5 cm long at 22.2°C is heated to114°C. What is its new length? Aluminum has a linear expansioncoefficient of 25 x 10-6 /C°.
Length of bar at final temperature in cm?

Explanation / Answer

Given: Linear expansion coefficient = 25 x 10-6/C° T = (114 - 22.2) = 91.8 oC L = 33.5 cm = 0.335 m Solve for L': L' = L + L = L + T*L = L (1+T) = 0.335(1+ 25 x 10-6 * 91.8) = 0.3358 m =33.58 cm *This equation works well if the linear expansion coefficientdoesn't change much over the change in temperatureT.

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