Objects with masses of 285 kg and a585 kg are separated by 0.460 m. (a) Find the
ID: 1675918 • Letter: O
Question
Objects with masses of 285 kg and a585 kg are separated by 0.460 m. (a) Find the net gravitational force exerted bythese objects on a 30.0 kg objectplaced midway between them.1 N
(b) At what position (other than infinitely remote ones) can the30.0 kg object be placed so as toexperience a net force of zero?
2 m from the 585 kg mass (a) Find the net gravitational force exerted bythese objects on a 30.0 kg objectplaced midway between them.
1 N
(b) At what position (other than infinitely remote ones) can the30.0 kg object be placed so as toexperience a net force of zero?
2 m from the 585 kg mass
Explanation / Answer
Masses m = 285 kg
M = 585 kg
Separation r = 0.46 m
3 rd object mass m ‘ = 30 kg
(a). the net gravitational force exerted by these objects on a30.0 kg object placed midway between them is
F = [GMm’ / x ^ 2] –[Gmm ‘ / x^ 2]
= [Gm’ / x^ 2 ] [ M – m]
Where G = Gravitational constant = 6.67 * 10^ -11 N m^ 2/ kg^ 2
x = distance of the mid point from one of the object = r/ 2= 0.23m
plug the values we get F = (3.782* 10 ^ -8 ) [ 300 ]
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