A screen is placed 1.10 m behind a single slit. Thecentral maximum in the result

Question

A screen is placed 1.10 m behind a single slit. Thecentral maximum in the resulting diffraction pattern on the screenis 1.80 cm wide-that is, the two first-order diffractionminima are separated by 1.80 cm. What is the distance between the two second-orderminima?    y2 =______ cm A screen is placed 1.10 m behind a single slit. Thecentral maximum in the resulting diffraction pattern on the screenis 1.80 cm wide-that is, the two first-order diffractionminima are separated by 1.80 cm. What is the distance between the two second-orderminima?    y2 =______ cm

Explanation / Answer

we have condition for diffraction minima sin=k*/b k=1 centre maxima 1.8cm =/b*L L=1.1 m k=2 => x=2/b*L= 3.6 cm

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