An engraver uses a magnifying glass ( f = 9.30 cm) toexamine some work, as in th

Question

An engraver uses a magnifying glass (f = 9.30 cm) toexamine some work, as in the drawing. The image he sees is located24.0 cm from his eye, which is his near point. (a)What is the distance between the work and the magnifying glass?(b) What is the angular magnification of themagnifying glass?

An engraver uses a magnifying glass (f = 9.30 cm) toexamine some work, as in the drawing. The image he sees is located24.0 cm from his eye, which is his near point. (a)What is the distance between the work and the magnifying glass?(b) What is the angular magnification of themagnifying glass?

Explanation / Answer

Given :    Focal length ( f ) = 9.30 cm Image distance ( di ) = -24.0 cm ( Image is virtual) a ) As we know that      From the lens equation    1/f = 1/do + 1/di    1/do = 1/f - 1/di            = 1/ 9.3 + 1/ 24.0       do = ---- cm Solve it b )      Near point of engraver is(N) = 24.0cm Angular magnification ( M ) = ( 1/f - 1/di ) N Solve it   

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