A clay ball with mass of .05kg is dropped from a height of 10cm and sticks to th

Question

A clay ball with mass of .05kg is dropped from a height of 10cm and sticks to the table. What is the impulse exerted on the clay ball? If the collision of the clay ball with the table takes the same 30ms as the collision of the superball, calculate the average force exerted by the table on the clay ball. Suppose the clay has twice the mass and is dropped from the same height. What is the impulse exerted on the ball by the table? Suppose the original clay ball (m=.05 kg) is dropped from twice the height, What is the impulse exerted on the ball by the table?

Explanation / Answer

Impulse is given as the product of force and time    I = F .t The force on the clay is the weight. impulse is         I =(0.05)(9.8)(30x10^-3s)           =0.147kgm/s if the mass is doubled then the impulse is laosdoubled.     I = 0.294kgm/s if the height is changed, the force exerted is same. sono change in impulse.      I = 0.147kgm/s

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