A 0.252 kg block is dropped straight downwards onto a certicalspring. The spring

Question

A 0.252 kg block is dropped straight downwards onto a certicalspring. The spring constant of the spring is 61 N/m. The block sticks to the spring and the spring compresses 0.15mbefore coming to a momentary halt. What is the speed of theblock just before it hits the spring? This is what I tried and it didn't work:       V=(Kx2/m-2gx) A 0.252 kg block is dropped straight downwards onto a certicalspring. The spring constant of the spring is 61 N/m. The block sticks to the spring and the spring compresses 0.15mbefore coming to a momentary halt. What is the speed of theblock just before it hits the spring? This is what I tried and it didn't work:       V=(Kx2/m-2gx)

Explanation / Answer

Let the acceleration of the block when the spring is compressedbe a.

The force acting on the block is

F = k * x

or m * a = k * x

or a = (k * x/m)

where k = 61 N/m,x = 0.15 m and m = 0.252 kg

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