A 500 turn solenoid with a length of 20 cmand a radius of 2.0 cm carries a curre

Question

A 500 turn solenoid with a length of 20 cmand a radius of 2.0 cm carries a currentof 2.0 A. A second coil of four turns iswrapped tightly about this solenoid so that it can be considered tohave the same radius as the solenoid. Find the following when thecurrent in the solenoid increases to 6.0 Ain a period of 0.90 s. (a) the change in the magnetic flux through thecoil
1T·m2
(b) the magnitude of the average induced emf in the coil
2 V (a) the change in the magnetic flux through thecoil
1T·m2
(b) the magnitude of the average induced emf in the coil
2 V

Explanation / Answer

   a.   Magnetic flux throughthe coil2         2   =   0* N1 * I1 * A * N2 /L                                                                         =   4 * 10-7 * 500 * 6.0 * ( * 0.022)* 4 / 0.20                                                                         =   9.47*10-5         T- m2       Change influx   =   final flux - initialflux                                  =   2- 0                               =   9.47* 10-5   T-m2       b.   Magnitudeon induced EMF      E   =   / t                                                                   =   9.47* 10-5 / 0.90                                                                   =   1.052* 10-4   V

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