A roller coaster starts from rest at top of a hill 70.0 mhigh.The car travels to

Question

A roller coaster starts from rest at top of a hill 70.0 mhigh.The car travels to the bottom of the next hill measuring 10.0m high.If the mass of the car is 725kg. how fast the car moving atthe top of the 10.0 m hill,if friction is ignored. Please help as soon u can. A roller coaster starts from rest at top of a hill 70.0 mhigh.The car travels to the bottom of the next hill measuring 10.0m high.If the mass of the car is 725kg. how fast the car moving atthe top of the 10.0 m hill,if friction is ignored. Please help as soon u can.

Explanation / Answer

In response to your comment on my page asking for moreinfo: According to the law of conservation of energy: energy isneither created nor destroyed Work Done byinitally conservatitve forces - Work done by non conservativeforces = Work finally done by conservative forces Non conservative forces are things like friction where energyis loss to heat not all of the mechanical energy isconserved. . For the purposes of this problem there is no non conservativeforces at play so the amount of energy will remain constant intial = final . For this example all of the energy is stored in gravitationalpotential energy which is equal to mgh, because the cart is notmoving non of the energy is kinetic ( 1/2mV2 where v=0so kinetic energy = 0) . so the energy equation looks like this mgh0 + 1/2mV02 =mghf + 1/2mVf2 The inital velocity is 0 so that cancels out1/2mV02 Our inital heigh is 70m our final height is 10m Our final Velocity is unknown so we will solve forit Our mass is in every part of the equation so we can simplydivide by m to cancel it out in every term and to simplify themath So now lets plug in the numbers: mgh = mgh + 1/2mV2 g x 70 = g x 10 + 1/2 x V2 V = 34.29 m/s Cheers Hope this was the detail you were looking for The inital velocity is 0 so that cancels out1/2mV02 Our inital heigh is 70m our final height is 10m Our final Velocity is unknown so we will solve forit Our mass is in every part of the equation so we can simplydivide by m to cancel it out in every term and to simplify themath So now lets plug in the numbers: mgh = mgh + 1/2mV2 g x 70 = g x 10 + 1/2 x V2 V = 34.29 m/s mgh = mgh + 1/2mV2 g x 70 = g x 10 + 1/2 x V2 V = 34.29 m/s V = 34.29 m/s Cheers Hope this was the detail you were looking for

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