I\'m having trouble setting up this problem. I need help asap!Thanks. A 5.0 kg w

Question

I'm having trouble setting up this problem. I need help asap!Thanks.
A 5.0 kg wooden block is placed on an adjustable wooden inclinedplane. (hint: For wood onwood, s is approximately .58and k is approximately .40 .) (a) What is the angle of incline above which the block will startto slide down the plane?
°

(b) At what angle of incline will the block then slide down theplane at a constant speed?
° I'm having trouble setting up this problem. I need help asap!Thanks.
(a) What is the angle of incline above which the block will startto slide down the plane?
°

(b) At what angle of incline will the block then slide down theplane at a constant speed?
°

Explanation / Answer

It will start sliding when gravity acting on the block is greaterthan static friction. Find the point where they're in equilibrium: N=cos()*mg Ns=sin()*mg cos()*mg*s=sin()*mg 0.58=tan() =30.11 The block will start sliding when the angle of inclination isgreater than 30.11 degrees Part b is similar, but the block is sliding; thus, the constant ofkinetic friction should be used instead. (The system is inequilibrium if ma =0 ) So, you can use the formula above and get: 0.40=tan() =21.8

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