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ID: 1672651 • Letter: X
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x.Hmellpadding="0" cellspacing="0" border="0"> Question Details: Consider a concave spherical mirror with a radius of curvature equal to 60.0 centimeters. An object 6.00 centimeters tall is placed along the axis of the mirror, 45.0 centimeters from the mirror. You are to find the location and height of the image. -What is the focal length of this mirror? -Now use the spherical mirror equation to find the image distance . -Find the magnification , using and . -Finally, use the magnification to find the height of the image . -Solve the spherical mirror equation for . x.Hmellpadding= 0 cellspacing= 0 border= 0 style= margin-top: 0px; margin-right: 0px; margin-bottom: 0px; margin-left: 0px; padding-top: 0px; padding-right: 0px; padding-bottom: 0px; padding-left: 0px; list-style-type: none; list-style-position: initial; list-style-image: initial; border-collapse: collapse; -webkit-border-horizontal-spacing: 0px; -webkit-border-vertical-spacing: 0px; > Question Details: Consider a concave spherical mirror with a radius of curvature equal to 60.0 centimeters. An object 6.00 centimeters tall is placed along the axis of the mirror, 45.0 centimeters from the mirror. You are to find the location and height of the image. -What is the focal length f of this mirror? -Now use the spherical mirror equation to find the image distance s'. -Find the magnification m , using s and s' . -Finally, use the magnification to find the height of the image y' . -Solve the spherical mirror equation for s' .Explanation / Answer
f = R/2 where R is the radius of curvature = 60cm/2 =30cm Since the object is outside the focal length, the imageis real and s' should be positive 1/f = 1/s + 1/s' 1/30 -1/45 = image distance will be 90cm m = s'/s = 90/45 = 2x m = y'/y so y' = m*y = 2*6cm = 12cm Hope that helpsRelated Questions
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