If a force a 5.0 N acted on a 0.5-kg block for a distance of7.0 m, what would be

Question

If a force a 5.0 N acted on a 0.5-kg block for a distance of7.0 m, what would be the velocity of the block_____m/s What is the potential energy of a 3.10- kg object at thebottom of a well 12.6 m deep as measured from groundlevel?______J explain the sign of the answer_________ An object is dropped from a height of 13 m. At what heightwill its kinetic energy and its potential energy beequal________m If a force a 5.0 N acted on a 0.5-kg block for a distance of7.0 m, what would be the velocity of the block_____m/s What is the potential energy of a 3.10- kg object at thebottom of a well 12.6 m deep as measured from groundlevel?______J explain the sign of the answer_________ An object is dropped from a height of 13 m. At what heightwill its kinetic energy and its potential energy beequal________m

Explanation / Answer

1)The force acting on the block is F = m * a or a = (F/m) where F = 5.0 N and m = 0.5 kg The velocity of the block is v = (2aS)1/2 where S = 7.0 m 2)The potential energy of the object at the bottom of the wellis U = m * g * h where m = 3.10 kg,g = 9.8 m/s2 and h = 12.6m The sign of the answer is positive as the potential energy ofthe object increases as it goes down into the well. 3)The point where its kinetic energy is equal to its potentialenergy is (1/2)m * v2 = m * g * h or v = (2gh)1/2 g = 9.8 m/s2 The height at which its kinetic energy is equal to itspotential energy is h = (v2/2g) The height at which its kinetic energy is equal to itspotential energy is h = (v2/2g)

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