(a) How long does it take the solenoid currentto reach 0.632 times its maximum v
ID: 1672243 • Letter: #
Question
(a) How long does it take the solenoid currentto reach 0.632 times its maximum value?1 s
(b) Determine the average back emf caused by the self-inductance ofthe solenoid during this interval. The magnetic field produced bythe solenoid at the location of the coil is one-half as strong asthe field at the center of the solenoid.
2 V
(c) Determine the average rate of change in magnetic flux througheach turn of the coil during the stated interval.
3 V
(d) Find the magnitude of the average induced current in thecoil.
4 A An 800-turn wire coil of resistance 24.0 ohm is placed on top of a 6.60 cm longsolenoid with N1 = 12200 turns, as in the figure below. Both coil andsolenoid have cross-sectional areas of 1.31 x 10^-4 m^2. (a) How long does it take the solenoid currentto reach 0.632 times its maximum value? 1 s (b) Determine the average back emf caused by the self-inductance ofthe solenoid during this interval. The magnetic field produced bythe solenoid at the location of the coil is one-half as strong asthe field at the center of the solenoid. 2 V (c) Determine the average rate of change in magnetic flux througheach turn of the coil during the stated interval. 3 V (d) Find the magnitude of the average induced current in thecoil. 4 A
Explanation / Answer
(a)
the current in the solenoid reaches
I = 0.632 Imax in the time
t =
= L / R
where
L = o N2 A / a
= .......... H
t = ........ s
(b)
the change in thesolenoid current during thistime is
I = 0.632 Imax - 0
= 0.632 (V /R)
= 0.632 (60 V / R)
= ........... A
back = L (I /t)
=........ V
(c)
B / t = (B) A/ t
= (1 / 2) [o n (I)] A / t
=.......... V
(d)
I = coil / Rcoil
= Ncoil (B /t) / Rcoil
= ......... A
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