Luggage is transported from one location to another in anairport by a conveyor b

Question

Luggage is transported from one location to another in anairport by a conveyor belt. At a certain location, the belt movesdown an incline that makes an angle of 1.7° with thehorizontal. Assume that with such a slight angle there is noslipping of the luggage. Determine the frictional force, includingsign, by the belt on a box weighing 60 N when the box is on theinclined portion of the belt and the belt speed is(a) 0 and constant, (b) 0.65 m/sand constant, (c) 0.65 m/s and increasing at arate of 0.16 m/s2, (d) 0.65 m/s anddecreasing at a rate of 0.16 m/s2, and(e) 0.65 m/s and increasing at a rate of 0.53m/s2. Take the positive direction to be up theincline.

Explanation / Answer

a.) Fnet = Fx -Ff ma = mgsin - Ff ma -mgsin = Ff 0 - 60N *sin1.7o = Ff Ff = -1.78N b.) Fnet = Fx -Ff ma = mgsin - Ff ma -mgsin = Ff 0 - 60N *sin1.7o = Ff Ff = -1.78N c.)  Fnet = Fx -Ff ma = mgsin - Ff ma -mgsin = Ff 0.16*9.18kg - 60N *sin1.7o = Ff Ff = -.212N d.) Fnet = Fx -Ff ma = mgsin - Ff ma -mgsin = Ff -.16 *9.18kg - 60N *sin1.7o =Ff Ff = -3.24N e.) Fnet = Fx -Ff ma = mgsin - Ff ma -mgsin = Ff .53*9.18kg - 60N *sin1.7o = Ff Ff = 3.084N Hope that helps ma = mgsin - Ff ma -mgsin = Ff 0 - 60N *sin1.7o = Ff Ff = -1.78N c.)  Fnet = Fx -Ff ma = mgsin - Ff ma -mgsin = Ff 0.16*9.18kg - 60N *sin1.7o = Ff Ff = -.212N d.) Fnet = Fx -Ff ma = mgsin - Ff ma -mgsin = Ff -.16 *9.18kg - 60N *sin1.7o =Ff Ff = -3.24N e.) Fnet = Fx -Ff ma = mgsin - Ff ma -mgsin = Ff .53*9.18kg - 60N *sin1.7o = Ff Ff = 3.084N Hope that helps ma = mgsin - Ff ma -mgsin = Ff 0.16*9.18kg - 60N *sin1.7o = Ff Ff = -.212N d.) Fnet = Fx -Ff ma = mgsin - Ff ma -mgsin = Ff -.16 *9.18kg - 60N *sin1.7o =Ff Ff = -3.24N e.) Fnet = Fx -Ff ma = mgsin - Ff ma -mgsin = Ff .53*9.18kg - 60N *sin1.7o = Ff Ff = 3.084N Hope that helps ma = mgsin - Ff ma -mgsin = Ff -.16 *9.18kg - 60N *sin1.7o =Ff Ff = -3.24N e.) Fnet = Fx -Ff ma = mgsin - Ff ma -mgsin = Ff .53*9.18kg - 60N *sin1.7o = Ff Ff = 3.084N Hope that helps ma = mgsin - Ff ma -mgsin = Ff .53*9.18kg - 60N *sin1.7o = Ff Ff = 3.084N Hope that helps

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