A student sits at rest on a piano stool that can rotatewithout friction. The mom

Question

A student sits at rest on a piano stool that can rotatewithout friction. The moment of inertia of the student-stool systemis 3.7 kg · m2. A secondstudent tosses a 1.4-kg mass with a speedof 2.2 m/s to the student on the stool,who catches it at a distance of 0.44 mfrom the axis of rotation. The final angular speed is 0.341 rad/s. Find initial KE and final KE. A student sits at rest on a piano stool that can rotatewithout friction. The moment of inertia of the student-stool systemis 3.7 kg · m2. A secondstudent tosses a 1.4-kg mass with a speedof 2.2 m/s to the student on the stool,who catches it at a distance of 0.44 mfrom the axis of rotation. The final angular speed is 0.341 rad/s. Find initial KE and final KE.

Explanation / Answer

Total moment of inertia of student -stool -mass 3,7+1,4*0,44^2=4,7(kg.m^2). Final KE K=0,5*^2*4,7=0,18(J). Initial KE. K=0,5*1,4*2,2^2=3,388(J)

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