(a) What is the magnitude of the pulley\'s angular acceleration? rad/s 2 (b) Wha

Question

(a) What is the magnitude of the pulley's angular acceleration?
rad/s2

(b) What is the magnitude of either block's acceleration?
m/s2

(c) What is the string tension T1?
N

(d) What is the string tension T2?
N

Explanation / Answer

= 1.10 / 72 x 10-3 = 15.27 rad/s R = 1.75 cm = 0.0175 m acceleration of the blocks a = 2R=4.084m/s2 We have from fig      m1g - T1 = m1a ==> T1 = m1(a+g) =7.80 * (13.88) = 108.30 N      T2 = m2a   = 7.80 * 4.084 =31.855 N      ( T1 - T2)R = I (a) angular acceleration                   = (T1- T2) R / I                      = (108.30 -31.855) * 0.0175 / 3.8 x 10-4                      = 3934 rad / s2 (b) a = 4.048 m/s2 (c) T1 = 108.30 N    (d) T2 = 31.855 N

Related Questions

Navigate

• Browse (All)
• Browse #
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.