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MA = +RB(40ft) - (5k)(32ft) - (1k/ft)(40ft)(20ft) =0 RB = +24k MB = -RA(40ft) +

ID: 1671057 • Letter: M

Question

MA = +RB(40ft) - (5k)(32ft) - (1k/ft)(40ft)(20ft) =0 RB = +24k MB = -RA(40ft) + (5k)(8ft) + (1k/ft)(40ft)(20ft) =0 RA = +21k 1) could you explain how the math works inoder to solve thisequation as well why is RB subtraction and RA addition. Is thatalways the case? MA = +RB(40ft) - (5k)(32ft) - (1k/ft)(40ft)(20ft) =0 RB = +24k MB = -RA(40ft) + (5k)(8ft) + (1k/ft)(40ft)(20ft) =0 RA = +21k 1) could you explain how the math works inoder to solve thisequation as well why is RB subtraction and RA addition. Is thatalways the case?

Explanation / Answer


MA = +RB(40ft) - (5k)(32ft) - (1k/ft)(40ft)(20ft) =0

               RB(40ft) - (5k)(32ft) - (1k/ft)(40ft)(20ft) = 0
               RB(40ft) = (5k)(32ft) + (1k/ft)(40ft)(20ft)
               RB          = [(5k)(32ft) + (1k/ft)(40ft)(20ft)] / 40ft
                              = [ 4 k + 20k ]
      = 24k

MB = -RA(40ft) + (5k)(8ft) + (1k/ft)(40ft)(20ft)= 0

               -RA(40ft) + (5k)(8ft) + (1k/ft)(40ft)(20ft) = 0
                RA(40ft) = (5k)(8ft) + (1k/ft)(40ft)(20ft)
                RA          = [(5k)(8ft) + (1k/ft)(40ft)(20ft)] / (40ft)
                                = [ 1k + 20k]
      = +21k