The radius of curvature of a loop-the-loop for a rollercoaster is 10.6 m. At the

Question

The radius of curvature of a loop-the-loop for a rollercoaster is 10.6 m. At the top of the loop,the force that the seat exerts on a passenger of mass m is0.70mg. Find the speed of theroller coaster at the top of the loop. (Enter your answers fromsmallest to largest.)
m/s
m/s The radius of curvature of a loop-the-loop for a rollercoaster is 10.6 m. At the top of the loop,the force that the seat exerts on a passenger of mass m is0.70mg. Find the speed of theroller coaster at the top of the loop. (Enter your answers fromsmallest to largest.)
m/s
m/s

Explanation / Answer

The velocity at the top of the roller coaster                     v = 0.70 * g r   = 0.70 * 9.8 * 10.6= 8.527 m/s The velocity at the bottom of the loop is                     v = 5 * 0.70 g r                        = 5 * 0.70 * 9.8 * 10.6 = 19.06m/s

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