0.5 kg mass exhibitng counterclockwise UCM on level fricfree tabletop at the end

Question

0.5 kg mass exhibitng counterclockwise UCM on level fricfree tabletop at the end of string whihc is held in place below asmall fric free hole thru whihc the string has been threaded.
a) if radius of circular motion = 0.5m and angular freq() =2sec -1. what is mass' KE? angular momentum? 0.5 kg mass exhibitng counterclockwise UCM on level fricfree tabletop at the end of string whihc is held in place below asmall fric free hole thru whihc the string has been threaded.
a) if radius of circular motion = 0.5m and angular freq() =2sec -1. what is mass' KE? angular momentum?

Explanation / Answer

We know that angular momentum L = mr2                                                        = 0.5 * 2 * 0.5*0.5 = 0.25 kgm2 /s Kinetic energy KE = 0.5 mv2 = 0.5 mr2 2 = 0.5 * 0.5 *(0.5)2 * 22 = 0.25 J

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