A 3.9 m long steel wire has across-section area of 0.046 cm 2 . Its proportional

Question

A 3.9 m long steel wire has across-section area of 0.046 cm2. Its proportional limit hasa value of 0.0015 times itsYoung's modulus (see table). Its breaking stress has a valueof 0.0064 times its Young'smodulus. The wire is fastened at its upper end and hangsvertically.
How great a weight can be hung from the wire withoutexceeding the proportional limit?

How much will the wire stretch under this load?
How great a weight can be hung from the wire withoutexceeding the proportional limit?

How much will the wire stretch under this load?

Explanation / Answer

Young's modulus of steel, Y = 200x109N/m2
Stress S = F/A = 0.0015xY             = 0.30x109 N/m2 Weight, F = SxA =0.30x109 x0.046x10-4                = 1380 N = 141kg.wt. Weight, F = SxA =0.30x109 x0.046x10-4                = 1380 N = 141kg.wt.

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