1) A flat loop of wire consisting of a single turn ofcross-sectional area 7.90 c

Question

1) A flat loop of wire consisting of a single turn ofcross-sectional area 7.90 cm2is perpendicular to a magnetic field that increases uniformly inmagnitude from 0.500 T to 3.50 T in1.00 s. What is the resulting inducedcurrent if the loop has a resistance of 1.30 ?

mA
1) A flat loop of wire consisting of a single turn ofcross-sectional area 7.90 cm2is perpendicular to a magnetic field that increases uniformly inmagnitude from 0.500 T to 3.50 T in1.00 s. What is the resulting inducedcurrent if the loop has a resistance of 1.30 ?

mA

Explanation / Answer

E=(Bf-Bi)*A/t=(3.5-0.5)*7.9*10^-4/1=2.37*10^-3 V I=E/R=1.823 mA

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