A jet flying at 325 m/s banks to make a horizontal circularturn. The radius of t

Question

A jet flying at 325 m/s banks to make a horizontal circularturn. The radius of the circle is 5.23×105m. The mass of the jet is 2.5×105 kg. What is the angle that the jet banks? What is the magnitudeof the lifting force?

I know my respect score is zero, but I will definitely give6 points to any one who can answer this for me thisevening.

Explanation / Answer

The vertical component is         L cos = mg The horizontal component        L sin = mv2 /R From above two relations we get          sin /cos = v2 / gR     ==> = tan-1 ( v2 / gR )               = tan-1 ( 3252 / 9.8 * 5.23 x 105 )               = 1.18o Therefore the lifting force            L = mg/ cos = 2.5 x 105 * 9.8 / cos1.18                                   = 24.50 x 105 N

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.